Nalorphene (C₁₉ H₂₁ NO₃) similar to morphine, is used to combat withdrawl symptoms in narcotic users. Dose of nalophene generally given is 1.5 mg. Calculate the mass of 1.5 x10^–3 m aqueous solution required for the above dose.

Solution

Molar Mass of C₁₉ H₁₂ NO₃= 19 x 12 + 21 x 1 + 14 + 48
= 228 + 21 + 14 + 48
= 311 g mol^{–1
$Molality (m) = \frac{Mass of solute / molarmass}{Mass of solvant in kg} 1.5 = \frac{Mass of solute / 311}{11} or 1.5 = \frac{Mass of solute}{311} or Mass of solute = 1.5 \times 10^{- 3} \times 311 = 0.4665 g$}

Mass of total solution = 1000 g + 0.467 g = 1000.467 g

To convert 1.5 g of nalorphene in to g divide by 1000 we get

1.5 mg / 1000 = 0.0015 g

Thus, 0.467 g mass of nalorphene contain

by = 1000.467 g solution

for 0.0015 g mass of nalorphene contain

by = 1000.467 × 0.0015/0.467

= 3.21 g.

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Solutions

Nalorphene (C₁₉ H₂₁ NO₃) similar to morphine, is used to combat withdrawl symptoms in narcotic users. Dose of nalophene generally given is 1.5 mg. Calculate the mass of 1.5 x10^–3 m aqueous solution required for the above dose.

Some More Questions From Solutions Chapter

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

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Solutions

Nalorphene (C19 H21 NO3) similar to morphine, is used to combat withdrawl symptoms in narcotic users. Dose of nalophene generally given is 1.5 mg. Calculate the mass of 1.5 x10–3 m aqueous solution required for the above dose.

Some More Questions From Solutions Chapter

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Nalorphene (C₁₉ H₂₁ NO₃) similar to morphine, is used to combat withdrawl symptoms in narcotic users. Dose of nalophene generally given is 1.5 mg. Calculate the mass of 1.5 x10^–3 m aqueous solution required for the above dose.