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Question
CBSEENCH12005740

Calculate the depression in the freezing of water when 10 g of CH3CH2CHCICOOH is added to 250 g of water. Ka = 1.4 x 10–3, K= 1.86 K kg moL–1

Solution

Answer:

We have given 
w2 = 10g
w1 = 250
Kf = 1.86k kg mol-1
M2 = 122.5
Mol. mass of CH3CH2CHCICOOH
     
=12+3+12+2+12+1×35.5+12+16+6+1= 122.5 g mol-1Tf = Kf×ω2×1000M2×ω1        = 1.86×10×1000122.5×250=  0.61°