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Solutions

Question

The partial pressure of ethane over a solution containing 6.56 x 10^–3 g of ethane is 1 bar. If the solution contains 5.00 x 10^–2 g of ethane, then what shall be the partial pressure of th gas?

Solution

By Henry's law, we can write,
P(C₂H₆ )= K_H x mole fraction of gas in sol

1 bar = K_{H} x conc . of gas in sol = K_{H} x 6.56 x 10^{- 2} g of C_{2} H_{6} K_{H} = \frac{1}{6.56 \times 10^{- 2}}

p' C_{2} H_{6} = K_{H} \times conc . of gas in sol = \frac{1}{6.56 \times 10^{- 2}} \times 5.00 \times 10^{- 2} = \frac{5}{6.56} = 0.762 bar .