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The Solid State

Question
CBSEENCH12005513

An atom has fcc crystal whose density is 10 gm–3 and cell edge is 100 pm. How many atoms are present in its 100 g?

Solution

Solution:
We have given that
Density = 10 gm-3
Mass = 100g
edge of unit cell ,a= 4 since it is a Fcc crystal

we have to find total number of atom, So by following relation we can get the result,

Total No. of atoms = Z×Ma3.d

Therefore, number of atoms

=4×100 g(100×10-12m)3×10 gm-3= 4×1031 atoms
 
thus the number of atoms is 4 x 1031