Question
An atom has fcc crystal whose density is 10 gm–3 and cell edge is 100 pm. How many atoms are present in its 100 g?
Solution
Solution:
We have given that
Density = 10 gm-3
Mass = 100g
edge of unit cell ,a= 4 since it is a Fcc crystal
we have to find total number of atom, So by following relation we can get the result,
Total No. of atoms =
Therefore, number of atoms
thus the number of atoms is 4 x 1031