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The Solid State

Question
CBSEENCH12005510

Calculate the density of silver which crystallizes in a face centred cubic lattice with unit cell length 0.4086 nm (At. mass of Ag = 107.88)

Solution

 Solution:
We have given that

Unit cell length,
a = 0.40806 nm  = 4.086 x 10-10 m

  If fcc lattice the number of atoms per unit cell,
i.e. Z = 4

        M for Ag = 107.88 g mol-1

                      =1.0788×10-1 kg mol-1

              NA = 6.023 × 1023


Density of Ag, d = ZMNA a3

                         = 4×1.0788×10-16.023×1023×(4.086×10-10)3= 1.051 × 104 kg m-3

 Thus the density of silver is 1.051 x 104 kgm-3