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The Solid State

Question
CBSEENCH12005590

The density of KBr is 2.75 g cm–3. The length of the edge of the unit cell is 654 pm. Show that KBr has a fcc structure.

Solution

we know that

d= ZMa3NA

as given that,
density= 2.75 g cm–3
a = 654 pm or a3 = 2.79 x 10-23
mass of KBr is 119 gram



Z =2.75 x6.54 x10-23 x6.022 x1023119 =4