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The Solid State

Question
CBSEENCH12005496

Aluminium crystallizes in a cubic close-packed structure. Its metallic radius is 125 pm.
(a) What is the length of the side of the unit cell?
(b) How many unit cells are there in 1.00 cm3 of aluminium?

Solution

Given, radius of atom (r) = 125 pm
(a) For ccp structure, we know that,

straight r equals space fraction numerator straight a over denominator 2 square root of 2 end fraction

where comma space straight r space equals space radius space and space straight a space equals space length space of space side space
equals space 125 space pm space equals space fraction numerator straight a over denominator 2 square root of 2 end fraction

straight a equals space 125 space straight x space 2 square root of 2

straight a equals 125 space straight x 2 space 1.414 space pm

straight a equals 353.5 space pm

left parenthesis straight b right parenthesis volume space of space 1 space unit space cell space equals straight a cubed

equals left parenthesis 353.5 space straight x space 10 to the power of negative 3 end exponent cm right parenthesis cubed
equals 44192902.36 space straight x 10 to the power of negative 30 end exponent space cm cubed
equals 442 space straight x space 10 to the power of negative 25 end exponent space cm cubed

Thus comma space number space of space unit space cell space of space aluminium space in space 1 space cm cubed

equals fraction numerator 1 cm cubed over denominator 442 space straight x space 10 to the power of negative 25 end exponent space cm cubed end fraction

equals 2.27 space straight x 10 to the power of 22 space unit space cell