What will be the correct order for the wavelength of absorption in the visible region for the following:
[Ni (NO2)6]4–, [Ni(NH3)6]2+, [Ni(H2O)6]2+?
The central metal atom is same in all compound. Thus adsorption in the visible reigon depend on the ligand. according to spectrochemical series increasing order of ligand is H2O < NH3 < NO2-. Hence the correct order for wavelength is
[Ni (NO2)6]4–<[Ni(NH3)6]2+<[Ni(H2O)6]2+.
(i) [Ni– (NO2)6]4– = wavelength of light is 498 nm.
(ii) [Ni(NH3)6]2+= wavelength of light is 475 nm.
(iii) [Ni(H2O)6]2+ = wavelength of light is 500nm.