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The D-And-f-Block Elements

Question
CBSEENCH12007125
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Calculate the number of unpaired electrons in following gaseous ions: Mn3+, Cr3+, V3+ and Ti3+, which one of these is the most stable in aqueous solution?

Solution

The number of unpaired electrons can be determined from their electronic configurations and are tabulated below:

Specie

Electronic

configuration

No. of unpaired electron

1.    Mn3+

[Ar] 3d44s0

4

2.    Cr3+

[Ar] 3d34s0

3

3.    V3+

[Ar] 3d24s0

2

4.    Ti3+

[Ar] 3d14s0

1


Out of these, Cr3+ is most stable in aqueous solution as its hydration energy is highest
.

Some More Questions From The d-And-f-Block Elements Chapter

Which is a stronger reducing agent Cr2+ or Fe2+ and why?

Explain why Cu+ ion is not stable in aqueous solutions?

Actinoid contraction is greater from element to element than lanthanoid contraction. Why?

On what ground can you say that scandium (Z = 21) is a transition element but zinc (Z = 30) is not?

The outer electronic configuration of copper is 3d10 4s1, yet it is considered transition element. Why?

Why the melting points of transition elements are high?

Why Zn, Cd and Hg are not regarded as transition elements?

Name the first element of 3rd transition series.

Though copper, silver and gold have completely filled sets of d-orbitals yet they are considered as transition metals. Why?

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