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Structure Of Atom

Question
CBSEENCH11008438

Given: The mass of electron is 9.11 x 10-31 kg
Planck constant is 6.626 x 10-34 Js,
the uncertainty involved in the measurement of velocity within a distance of 0.1 A is:

  • 5.79 x 106 ms-1

  • 5.79 x 107 ms-1

  • 5.79 x 108 ms-1

  • 5.79 x 105 ms-1

Solution

A.

5.79 x 106 ms-1

By Heisenberg's uncertainty principle
increment straight p space. increment straight x space greater or equal than space fraction numerator straight h over denominator 2 straight pi end fraction
or space increment straight v. increment straight x space greater or equal than fraction numerator straight h over denominator 4 πm end fraction
increment straight p space rightwards arrow space uncertainty space in space momentum
increment straight x space rightwards arrow space uncertainty space in space position
increment straight v space rightwards arrow space uncertainty space in space velocity
straight m rightwards arrow space mass space of space particle
Given comma
increment straight x space equals space 0.1 space straight A space equals space 0.1 space straight x space 10 to the power of negative 10 end exponent space straight m
straight m equals space 9.11 space straight x space 10 to the power of negative 31 end exponent space kg
straight h space equals space planck space constant space equals space 6.626 space straight x space 10 to the power of negative 34 end exponent space Js
straight pi space equals space 3.14
In space uncertain space position space increment straight v. increment straight x space equals space fraction numerator straight h over denominator 4 πm end fraction
increment straight v space straight x space 0.1 space straight x space 10 to the power of negative 10 end exponent space equals space fraction numerator 6.626 space straight x space 10 to the power of negative 34 end exponent over denominator 4 space straight x space 3.14 space straight x space 9.11 space straight x space 10 to the power of negative 31 end exponent end fraction
increment straight v space equals space fraction numerator 6.626 space straight x space 10 to the power of negative 34 end exponent over denominator 4 space straight x space 3.14 space straight x space 911 space straight x space 10 to the power of negative 31 end exponent straight x space 0.1 space straight x space 10 to the power of negative 1 end exponent end fraction ms to the power of negative 1 end exponent
equals space 5.785 space straight x space 10 to the power of 6 space ms to the power of negative 1 end exponent
5.79 space straight x space 10 to the power of 6 space ms to the power of negative 1 end exponent