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Some Basic Concepts Of Chemistry

Question
CBSEENCH11008415

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?

  • 0.044

  • 0.333

  • 0.011

  • 0.029

Solution

D.

0.029

The reagent which is present in smaller quantity is called the limiting reagent and the moles of product depends on it and number of moles
 
 =fraction numerator weight over denominator molecular space weight end fraction
PbO with 207.2 plus 16 below space space space space space space space plus stack space 2 space HCl space with 2 space left parenthesis 35.5 space plus 1 right parenthesis below space rightwards arrow space stack PbCl subscript 2 with 207.2 space plus 71 below space space space plus space space straight H subscript 2 straight O
space equals space 223.2 space space space space space space space space space space equals 73 space space space space space space space space space space space space space space space equals 278.2
Here, 1 mole of PbO reacts with 2 moles of HCl, thus PbO is the limiting reagent
because space 223.2 space straight g space PbO space gives space PbCl subscript 2 space equals space 278.2 space straight g
therefore space 6.5 space straight g space PbO space will space give space PbCl subscript 2
space equals space fraction numerator 278.2 over denominator 232.2 end fraction space straight x space 6.5 space straight g
equals space fraction numerator 278.2 space straight x space 6.5 over denominator 223.2 space straight x space 278.2 end fraction space mol
0.029 mol