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Chemical Bonding And Molecular Structure

Question
CBSEENCH11008412

The correct order of increasing bond angles in the following triatomic species is 

  • NO subscript 2 superscript minus space less than thin space NO subscript 2 superscript plus space thin space less than space NO subscript 2
  • NO subscript 2 superscript minus space less than thin space NO subscript 2 space less than thin space NO subscript 2 superscript plus
  • NO subscript 2 superscript plus space less than thin space NO subscript 2 space less than thin space NO subscript 2 superscript minus
  • NO subscript 2 superscript plus space less than thin space NO subscript 2 superscript minus space less than thin space NO subscript 2

Solution

B.

NO subscript 2 superscript minus space less than thin space NO subscript 2 space less than thin space NO subscript 2 superscript plus

As the number of lone pair of electrons increases, bond angle decreases. NO2+ ion is isoelectronic with the CO2 molecule. It is a linear ion and its central atom (N+) undergoes sp-hybridisation, hence bond angle is 180o.
In NO2- ion, N -atom undergoes sp2 hybridisation. The angle between hybrid orbital should be 120o but one lone pair of electrons is lying on N- atom, hence bond angle decreases to 115o.
In NO2 molecule, N -atom has one unpaired electron in a sp2-hybrid orbital. The bond angle should be 120o but actually, it is 132o. It may be due to one unpaired electron in a sp2-hybrid orbital.
Therefore, the increasing order of bond angles.
stack NO subscript 2 superscript minus space with 115 to the power of 0 below less than space stack NO subscript 2 with 132 to the power of 0 below space less than space stack NO subscript 2 superscript plus with 180 to the power of 0 below