Question
What volume of oxygen gas (O2) measured at 0oC and 1 atm, is needed to burn completely 1 L of propane gas (C3H8) measured under the same conditions?
-
7 L
-
6 L
-
5 L
-
10 L
Solution
C.
5 L
Volume of a gas at STP = 22.4 L
C3H 8 + 5O2 → 3CO2 + 4H2O
22.4 L 5 x 22.4 L
Therefore,
to burn 22.4 L C3H8 the oxygen required is
= 5 x 22.4 L
To burn 1 L C3H8 the oxygen required will be = 5 x 22.4 / 22.4 = 5 L
