Question
The electrons identified by quantum numbers n and l, are as follows
- n =4, l=1
-
n = 4, l = 0
-
n =3, l= 2
- n = 3, l = 1
If we arrange them in order of increasing energy, i.e., from lowest to highest, the correct order is
IV<II<III<I
II<IV<I<III
I < III < II < IV
III < I < IV < II
Solution
A.
IV<II<III<I
Reason:
(i) More be the sum of n + l → more be the energy.
(ii) For the
same sum, the more value of n, have higher energy.
Because, n + l for →
(a) 4 + 1 = 5
(b) 4 + 0 = 4
(c) 3+ 2 = 5
(d) 3+1 = 4
therefore, correct order is (iv)<(ii) < (iii) < (i)
