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Thermodynamics

Question
CBSEENCH11008484

The energy released when 6 moles of octane is burnt in air will be [Given, ΔHf for CO2 (g). H2O(g) and C8H18 (l), respectively are -490, -240 and +160J/mol]

  • -37.4 kJ

  • -20 kJ

  • -6.2 kJ

  • -35.5 kJ

Solution

D.

-35.5 kJ

C +O2   CO2; G = - 490 J ...(i)H2 + 12O2    H2O ; H =- 240 J ...(ii)8C + 9H2   C8H18; H = +160 J .... (iii)

On applying, 8 x Eq. (i)  + 9x Eq. (ii) -Eq. (iii), we get

C8H18 + 252O2   8CO2  + 9H2OHR0 = [8 x (-490)] + [9 x (-240)] + 160 = -5920 J mol-1

Hence, energy exchange when 6 moles of octane is burnt in air = - 5920 x 6 = -35520 J = -35.5 kJ