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Thermodynamics

Question
CBSEENCH11008475

The bond dissociation energies of X2, Y2 and XY are in the ratio of 1 : 0.5: 1. ΔH for the formation of XY is –200 kJ mol–1. The bond dissociation energy of X2 will be

  • 200 kJ mol-1

  • 100 kJ mol-1

  • 400 kJ mol-1

  • 800 kJ mol-1

Solution

D.

800 kJ mol-1

Let B.E of x2,y2 and xy are x kJ mol-1, 0.5 x kJ mol-1 and x kJ mol-1 respectively

12x2 + 12y2  xy;H = - 200 kJ mol-1H = - 200 = Σ(B.E)reactant - Σ(B.E)product = 12  x (x) +12 x (0.5)x-[1x (x)]On solving we get, B.E of X2 = x = 800 kJ mol-1