Question
In which case is a number of molecules of water maximum?
18 mL of water
0.18 g of water
10-3 mol of water
0.00224 L of water vapours at 1 atm and 273K
Solution
A.
18 mL of water
a) Mass of water = 18 x 1 = 18 g
Molecules of water = mole x NA
b) Molecules of water = mole x NA
c) Molecules of water = mole x NA = 10-3 NA
d) Moles of water = 0.00224/22.4 = 10-4
Molecules of water = mole x NA = 10-4 NA
