For a given reaction, ΔH = 35.5 kJ mol–1 and ΔS = 83.6 JK–1 mol–1. The reaction is spontaneous at (Assume that ΔH and ΔS do not vary with temperature)
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T < 425 K
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T > 425 K
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All temperatures
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T > 298 K
B.
T > 425 K
∵ ΔG = ΔH – TΔS
For a reaction to be spontaneous, ΔG = –ve
i.e., ΔH < TΔS
therefore, T> ΔH/ΔS
= 35.5 x 103J/83.6JK-1
i.e T>425 K