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Thermodynamics

Question
CBSEENCH11008462

For a given reaction, ΔH = 35.5 kJ mol–1 and ΔS = 83.6 JK–1 mol–1. The reaction is spontaneous at (Assume that ΔH and ΔS do not vary with temperature)

  • T < 425 K

  • T > 425 K

  • All temperatures

  •  T > 298 K

Solution

B.

T > 425 K

∵ ΔG = ΔH – TΔS
For a reaction to be spontaneous, ΔG = –ve
i.e., ΔH < TΔS

therefore, T> ΔH/ΔS
= 35.5 x 103J/83.6JK-1
i.e T>425 K