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The P-Block Elements

Question
CBSEENCH11008447

The correct regarding the electronegativity of hybrid orbitals of carbon is: 

  • sp> sp2<sp3

  • sp> sp2 > sp3

  • sp< sp2 > sp3

  • sp< sp2 < sp3

Solution

B.

sp> sp2 > sp3

The correct  order regarding the electronegativity of hybrid orbitals of carbon is sp> sp2 > sp3 because in sp> sp2 > and sp3 hybrid orbitals s- orbital character is 50%, 33.3% and 25% respectively and due to higher s-orbital character electron attraction tendency i,e, electronegativity increases.