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Equilibrium

Question
CBSEENCH11008441

For the reaction,

CH4  (g) + 2 O2 (g) ⇌ CO2 (g) + 2H2O (l), 

ΔrH = - 170. 8 kJ mol-1

Which of the following statements is not true? 

  • At equilibrium, the concentrations of CO2 (g) and H2O (l) are not equal

  • The equilibrium constant for the reaction is given by Kpfraction numerator left square bracket CO subscript 2 right square bracket over denominator left square bracket CH subscript 4 right square bracket left square bracket straight O subscript 2 right square bracket end fraction

  • Addition of CH4 (g) or O2 (g) at equilibrium will cause a shift to the right

  • The reaction is exothermic

Solution

B.

The equilibrium constant for the reaction is given by Kpfraction numerator left square bracket CO subscript 2 right square bracket over denominator left square bracket CH subscript 4 right square bracket left square bracket straight O subscript 2 right square bracket end fraction

For the reaction,
CH4  (g) + 2 O2 (g) ⇌ CO2 (g) + 2H2O (l), 
ΔrH = - 170. 8 kJ mol-1
This equilibrium is an example of heterogeneous chemical equilibrium.Hence, for it
straight K subscript straight c space equals space fraction numerator left square bracket CO subscript 2 right square bracket over denominator left square bracket CH subscript 4 right square bracket left square bracket straight O right square bracket squared end fraction space... space left parenthesis straight i right parenthesis
left parenthesis equilibrium space constant space on space the space basis space of space conc. right parenthesis
and space straight K subscript straight p space equals space fraction numerator straight P subscript Co subscript 2 end subscript over denominator straight P subscript CH subscript 4 end subscript space straight x space straight P subscript straight O subscript 2 end subscript squared space end fraction space space space space.... space left parenthesis ii right parenthesis
left parenthesis Equilibrium space constant space according space to space partial space pressure right parenthesis
Thus space in space it space concentration space of space CO subscript 2 space left parenthesis straight g right parenthesis space and space straight H subscript 2 straight O space left parenthesis straight l right parenthesis space are space not space equilibrium
The space equilibrium space constant space left parenthesis straight K subscript straight p right parenthesis space equals space fraction numerator left square bracket CO subscript 2 right square bracket over denominator left square bracket CH subscript 4 right square bracket left square bracket straight O subscript 2 right square bracket space end fraction
not correct expression.
In addition of CH4 (g) or O2 (g) at equilibrium Kc = will be decreased according to expression (i) but Kc remains constant at constant  at constant temperature fro a reaction, so for maintaining the constant value of Kc, the concentration of CO2 will increase in same order. Hence, on the addition of CH4 or O2 equilibrium will cause to the right.
This reaction is an example of an exothermic reaction.