Question

If the equilibrium constant for

$straight N subscript 2 space left parenthesis straight g right parenthesis space plus space straight O subscript 2 space left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space 2 space NO space left parenthesis straight g right parenthesis space is space straight K comma space the space equilibrium space constant space for 1 half straight N subscript 2 space left parenthesis straight g right parenthesis space plus space 1 half straight O subscript 2 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space NO space left parenthesis straight g right parenthesis space will space be$

K^1/2

K/2

K

K²

Solution

K^1/2

As we can see the reaction for which we have to find out equilibrium constant is different only in stoichiometric coefficient as compared to the given reaction. Hence, we can find equilibrium constant as,
$straight N subscript 2 space left parenthesis straight g right parenthesis space plus space straight O subscript 2 space left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space 2 space NO space left parenthesis straight g right parenthesis thin space is space straight K straight i. straight e. space straight K space equals space fraction numerator left square bracket NO right square bracket squared over denominator left square bracket straight N subscript 2 right square bracket left square bracket straight O subscript 2 right square bracket end fraction space space space.. space left parenthesis straight i right parenthesis Let space equilibrium space constant space for space the space reaction comma 1 half space straight N subscript 2 space left parenthesis straight g right parenthesis space plus space 1 half straight O subscript 2 space left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space 2 NO space left parenthesis straight g right parenthesis space is space straight K apostrophe straight i. straight e space space straight K apostrophe space equals space fraction numerator left square bracket NO right square bracket over denominator left square bracket straight N subscript 2 right square bracket to the power of 1 divided by 2 end exponent left square bracket straight O subscript 2 right square bracket to the power of 1 divided by 2 end exponent end fraction On space squaring space both space sides straight K apostrophe squared space equals space fraction numerator left square bracket NO right square bracket squared over denominator left square bracket straight N subscript 2 right square bracket left square bracket straight O subscript 2 right square bracket end fraction space space.. space left parenthesis ii right parenthesis On space comparing space Eqs. space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis space we space get straight K equals space straight K apostrophe squared or straight K to the power of apostrophe space equals space square root of straight K$

For Daily Free Study Material Join wiredfaculty

Equilibrium

Some More Questions From Equilibrium Chapter

Name the factors on which vapour pressure of any liquid depends.

Which measurable property becomes constant in water vapour equilibrium?

Give an example from daily life in which there is gas solution equilibrium?

A crystal of common salt of a given mass is kept in its aqueous solution. After 24 hours, its mass remains the same. Is the crystal in equilibrium with the solution?

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction