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Some Basic Concepts Of Chemistry

Question
CBSEENCH11008331
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What is the mass of precipitate formed when 50 mL of 16.9% solution of AgNO3 is mixed with 50 mL of 5.8% NaCl solution?

(Ag = 107.8, N = 14, O = 16, Na = 23, Cl = 35.5)


  • 28 g

  • 3.5 g 

  • 7 g 

  • 14 g 

Solution

C.

7 g 

For the calculation of the mass of AgCl precipitate, we find the mass of AgNO3 and NaCl in equal volume with the help of mole concept. 16.9% solution of AgNO3 means 16.9 g AgNO3 is present in 100 mL solution.
therefore, 8.45 g AgNO3 will present in 50 mL solution similarly,
5.8 g NaCl is present in 100 ml solution
stack space space space space space space space space space space space space space space space space space space space space space space space space with Initial space mole below space space stack space AgNO subscript 3 with fraction numerator 8.45 over denominator 169.8 end fraction below space plus space NaCl with fraction numerator 2.9 over denominator 58.5 end fraction space space space space space space below space rightwards arrow space AgCl with 0 below space plus space stack NaNO subscript 3 with 0 below space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.049 space space space space space equals 0.049 After space reaction space space space space space space 0 space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space 0.049 space space space space space space space space space 0.049 therefore comma space Mass space of space AgCl space precipitated space equals space 0.049 space straight x space 143.5 space equals 7 space straight g

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