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Structure Of Atom

Question
CBSEENCH11008313

The energies E1 and E2 of two radiations are 25 eV respectively. The relation between their wavelength i.e., λ1 and λ2 will be

  • λ1 = 2λ2

  • λ1 = 4λ2

  • λ1 = λ2/2

  • λ1 = λ2

Solution

A.

λ1 = 2λ2

E1 = 25eV. E2 = 50 eV
E1 = hc/λ1  and E2 = hc/λ2
fraction numerator straight E subscript 1 over denominator straight E subscript 2 space end fraction space equals space lambda subscript 1 over lambda subscript 2
p u t t i n g space t h e space g i v e n space v a l u e
25 over 50 space equals space lambda subscript 1 over lambda subscript 2
rightwards double arrow space lambda subscript 1 space equals space 2 lambda subscript 2