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Chemical Bonding And Molecular Structure

Question
CBSEENCH11008389
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The state of hybridization of C2, C3, C5 and C6 of the hydrocarbon,


is in the following sequence

  • sp, sp3, sp2 and sp3

  • sp3, sp2, sp2 and sp

  • sp,sp2,sp2 and sp3

  • sp, sp2, sp3 and sp2

Solution

A.

sp, sp3, sp2 and sp3

Count a number of sigma bond (σ) and then find hybridization as follows.
If number of σ bonds = 2; hybridization is sp,
If number of σ bonds = 3; hybridization is sp2
if the number of σ bonds = 4; hybridization is sp3


Double and triple bond is not considered while finding hybridization.

Some More Questions From Chemical Bonding and Molecular Structure Chapter

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(ii) a non-metal and another non-metal?

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Why sodium chloride is a solid whereas carbon tetrachloride is a liquid?

Why NaCl gives a white percipitate with AgNO3 solution but CCl4 does not?

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