Question
The pressure exerted by 6.0 g of methane gas in a 0.03 m3 vessel at 129o C is (Atomic masses C = 12.01, H = 1.01 and R = 8.314 JK-1 mol-1)
-
215216 Pa
-
13409 Pa
-
41648 Pa
-
31684 Pa
Solution
C.
41648 Pa
Given,
Volume , V = 0.03 m3
Temperature, T = 129 + 273 = 402 K
mass of methane, w = 6.0 g
mol. Mass of methane, M = 12.01 + 4 x 1.01 = 16.05
From, ideal gas equation,
pV = nRT
