Question
The reaction,
2A (g) + B (g) ⇌ 3C (g) + D (g)
is begun with the concentrations of A and B both at an initial value of 1.00 M. When equilibrium is reached, the concentration of D is measured and found to be 0.25 M. The value for the equilibrium constant for this reaction is given by the expression
-
[(0.75)3 (0.25)] / [(1.00)2 (1.00)]
-
[(0.75)3 (0.25) ] / [(0.50)2(0.75)]
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[(0.75)3(0.25)] / [(0.50)2(0.75)]
-
[(0.75)3(0.25)] - [(0.75)2(0.25)]
Solution
B.
[(0.75)3 (0.25) ] / [(0.50)2(0.75)]
