Question
If pH ofa saturated solution of Ba(OH)2 is 12, the value of its Ksp is
-
4.00 x 10-6 M3
-
4.00 x 10-7 M3
-
5.00 x 10-6 M3
-
5.00 x 10-7 M3
Solution
C.
5.00 x 10-6 M3
Given pH of Ba(OH)2 = 12
therefore, [H+] = [1 x 10-12]
and [OH-] = 1 x 10-14 / 1 x 10-12 {[H+][OH-] = 1 x 10-14}
