+91-8076753736 [email protected]

-->

Chemical Bonding And Molecular Structure

Question

Wired Faculty App

According to molecular orbital theory, which of the following will not be a viable molecule?

$H_{2}^{2 -}$

$H e_{2}^{2 +}$

$H e_{2}^{+}$

$H_{2}^{-}$

Solution

A.

$H_{2}^{2 -}$

Species	Bond Order
$H_{2}^{2 -}$	1/2[2-2] = 0 (does not exist)
$H e_{2}^{2 +}$	1/2[2-0] = 1 (Exist)
$H e_{2}^{2 -}$	1/2 [2-1] = 0.5 (Exist)
$H_{2}^{-}$	1/2 [ 2-1] = 0.5 (Exist)

Some More Questions From Chemical Bonding and Molecular Structure Chapter

Why do atoms combine?

Can ionic bond be formed between similar atoms?

Why two helium atoms do not combine to form He₂?

What are 'Lewis structures'?

Name the conditions for the formation of an ionic bond between two atoms.

What is crystal lattice?

What is electrovalency?

What bond is present in MgCl₂ molecules?

Write Lewis dot symbols for atoms of the elements Mg, Na, B, O, N, Br.

Draw the Lewis structure for the ionic compound by aluminium and fluorine.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation