Question
The ratio of mass percent of C and H of an organic compound (CXHYOZ) is 6: 1. If one molecule of the above compound (CXHYOZ) contains half as much oxygen as required to burn one molecule of compound CXHY completely to CO2 and H2O. The empirical formula of compound CXHYOZ is
C2H4O3
C3H6O3
C2H4O
C3H4O2
Solution
A.
C2H4O3
The ratio of mass % of C and H in CxHyOz is 6: 1.
Therefore,
The ratio of mole % of C and H in CxHyOz will be 1: 2.
Therefore x : y = 1 : 2, which is possible in options 1, 2 and 3.
Now oxygen required to burn CxHy
Now z is half of the oxygen atoms required to burn CxHy
Now putting values of x and y from the given options:
Option (1), x = 2, y = 4
