-->

States Of Matter

Question
CBSEENCH11008291

For real gases van der Waal's equation is written as,

open parentheses straight p space plus an squared over straight V squared close parentheses open parentheses straight V minus nb close parentheses space equals space nRT
where, a and b are van der Waal's constants.
Two sets of gases are

I. O2, CO2, H2 and He
II. CH4, O2, and H2

The gases given in set- I increasing order of 'b' and gases given in set -II in decreasing order of 'a' are arranged below. Select the correct order from the following.

  • (I) He < H2 < CO< O2
    (II)  CH4>  H2> O2

  • (I) O2 < He < H2 < CO2
    (II) H2> O2 > CH4

  • (I) O2 < He < O2 < CO2
    (II) CH4 > O2 > H2  

  • (I) H2 > O2 <He < CO2
    (II) O2 > CH4 > H2  

Solution

C.

(I) O2 < He < O2 < CO2
(II) CH4 > O2 > H2  

From experimental values of a and b, sequence of Van der Waals constant (b) is

Gas

H2

He

O2

CO2

Value of b

0.0273

0.0318

0.0273

0.0427

Hence correct order is

H2 < He < O2 < CO2

And sequence of van der Waals constant (a) is

Gas

CH4

O2

H2

Value of a

2.25

1.36

0.244

Hence, correct order is

(II) CH4 >O2> H2