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Structure Of Atom

Question
CBSEENCH11008290

The orbital angular momentum of p-electron is given as

  • fraction numerator straight h over denominator square root of 2 straight pi end root end fraction
  • square root of 3 fraction numerator h over denominator 2 pi end fraction
  • square root of 3 over 2 end root space h over pi
  • square root of 6. end root fraction numerator h over denominator 2 pi end fraction

Solution

A.

fraction numerator straight h over denominator square root of 2 straight pi end root end fraction

Orbital angular momentum = 
square root of straight l left parenthesis straight l plus 1 right parenthesis end root space x fraction numerator h over denominator 2 pi end fraction
therefore space F o r space p minus e l e c t r o n comma space l italic space italic equals italic 1
italic therefore italic space O r b i t a l italic space a n g u l a r italic space m o m e n t u m italic comma
italic equals italic space italic space square root of l italic left parenthesis l italic plus italic 1 italic right parenthesis end root space x fraction numerator h over denominator italic 2 pi end fraction
italic equals italic space square root of italic 2 italic space x fraction numerator h over denominator italic 2 pi end fraction
italic equals fraction numerator h over denominator square root of italic 2 pi end fraction