Question

Give that the equilibrium constant for the reaction,

2SO₂ (g) + O₂ (g) ⇌ 2SO₃ (g)

has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction t the same temperature?

SO₃ (g) ⇌ SO₂ (g) +1/2 O₂ (g)

1.8 x 10^-3

3.6 x 10^-3

6.0 x 10^-2

1.3 x 10^-5

Solution

6.0 x 10^-2

2SO₂ (g) +O₂ (g) ⇌ 2SO₃ (g)
Equilibrium constant for this reaction,
$straight K equals space fraction numerator left square bracket SO subscript 3 right square bracket squared over denominator left square bracket SO subscript 2 right square bracket squared left square bracket straight O subscript 2 right square bracket end fraction SO subscript 3 space left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space SO subscript 2 space left parenthesis straight g right parenthesis space plus 1 half space straight O subscript 2 space left parenthesis straight g right parenthesis Equilibrium space constant space for space this space reaction straight K apostrophe space equals space fraction numerator left square bracket SO subscript 2 right square bracket left square bracket straight O subscript 2 right square bracket to the power of begin display style 1 half end style end exponent over denominator left square bracket SO subscript 3 right square bracket end fraction On space squaring space eq. space left parenthesis ii right parenthesis thin space both space sides comma space we space have space left parenthesis straight K to the power of apostrophe right parenthesis squared space equals space fraction numerator left square bracket SO subscript 2 right square bracket left square bracket straight O subscript 2 right square bracket over denominator left square bracket SO subscript 3 right square bracket end fraction space equals space 1 over straight K equals 1 over 278 straight K apostrophe space equals space square root of 1 over 278 end root equals square root of 0.003597 end root equals space 5.99 space straight x space 10 to the power of negative 2 end exponent almost equal to space 6 space straight x space 10 to the power of negative 2 end exponent$

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Equilibrium

Some More Questions From Equilibrium Chapter

A crystal of common salt of a given mass is kept in its aqueous solution. After 24 hours, its mass remains the same. Is the crystal in equilibrium with the solution?

What is the role of forward and backward reactions at equilibrium of a reversible reaction?

What is a forward reaction?

What condition favours a reversible reaction?

What is a backward reaction?

What type of equilibrium is attained in a reversibe chemical change?

What is meant by a system at dynamic equilibrium?

discuss the effect of a catalyst on equilibrium ?

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