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Chemical Bonding And Molecular Structure

Question
CBSEENCH11008287
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The pair of species with t he same bond order is 

  • O22-, B2

  • O2+, NO+

  • NO, CO

  • N2, O2

Solution

A.

O22-, B2

straight sigma 1 straight s squared comma space straight sigma asterisk times 1 straight s squared comma space straight sigma 2 straight s squared comma straight sigma asterisk times 2 straight s squared comma straight sigma 2 straight p subscript straight z superscript 2 comma space straight pi 2 straight p subscript straight x superscript 2 almost equal to straight pi 2 straight p subscript straight y superscript 2 space comma space straight pi asterisk times 2 straight p subscript straight x superscript 2 almost equal to straight pi asterisk times 2 straight p subscript straight y superscript 2 Bond space order space space equals space fraction numerator straight N subscript straight b minus straight N subscript straight a over denominator 2 end fraction left parenthesis where space straight N subscript straight b space equals space number space of space electrons space in space bonding space molecular space orbital straight N subscript straight a space equals space number space of space electrons space in space anti minus bonding space molecular space orbital right parenthesis straight O subscript 2 superscript 2 minus end superscript space left parenthesis 8 plus 8 plus 2 equals 18 right parenthesis BO space equals space fraction numerator straight N subscript straight b minus straight N subscript straight a over denominator 2 end fraction space equals space fraction numerator 10 minus 8 over denominator 2 end fraction space equals 1 straight B subscript 2 space left parenthesis 5 plus 5 space equals space 10 right parenthesis space equals space straight sigma 1 straight s squared comma space straight sigma asterisk times 1 straight s squared comma space straight sigma 2 straight s squared comma straight sigma asterisk times 2 straight s squared comma straight pi 2 straight p subscript straight x superscript 1 almost equal to straight pi 2 straight p subscript straight y superscript 1 space BO equals space fraction numerator 6 minus 4 over denominator 2 end fraction similarly space comma space order space of semicolon straight O subscript 2 superscript plus space equals space 2.5 comma space NO to the power of plus space equals space 3 NO space equals space 2.5 comma space CO space equals space 3 straight N subscript 2 space equals space 3 space and space straight O subscript 2 space equals 2

Some More Questions From Chemical Bonding and Molecular Structure Chapter

What is electrovalency?

What bond is present in MgCl2 molecules?

Write Lewis dot symbols for atoms of the elements Mg, Na, B, O, N, Br.

Draw the Lewis structure for the ionic compound by aluminium and fluorine.

Two elements A and B have the electronic configuration as:
A = 1s22s22p63s2 and B = 1s22s22p5
Write the empirical formula of the substance containing A and B.

What type of bonding would you expect between:
(i) a metal and a non-metal
(ii) a non-metal and another non-metal?

Give reasons in one or two sentences for the observation that in their compounds non-metals form anions and not cations.

Out of Na and K, which will form a more stable ionic bond?

Which will have a greater lattice enthalpy: NaCl or MgO?

Is  a covalent molecule always formed between two similar atoms?

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