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Thermodynamics

Question
CBSEENCH11008276
Wired Faculty App

The enthalpy of fusion of water is 1.435 Kcal/mol. The molar entropy change for the melting of ice of at 0o C is

  • 10.52 cal/(mol K)

  • 21.04 cal/(mol K)

  • 5.260 cal/ (mol K)

  • 0.526 cal / (mol K)

Solution

C.

5.260 cal/ (mol K)

Molar entropy change for the melting of ice,
ΔS subscript melt end subscript space equals space fraction numerator increment straight H subscript fusion over denominator straight T end fraction equals space fraction numerator 1.435 space kcal divided by mol over denominator left parenthesis 0 plus 273 right parenthesis space straight K end fraction equals space 5.26 space straight x space 10 to the power of negative 3 end exponent space kcal divided by mol space straight K equals space 5.26 space cal divided by mol space straight K

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