Question
The correct set four quantum number for the valence electron of rubidium atom (z=37) is
-
5,1,1, +1/2
-
6,0,0,+1/2
-
5,0,0 +1/2
-
5,1,0, +1/2
Solution
C.
5,0,0 +1/2
37Rb = 36[Kr] 5s1Its valence electron is 5s1
so,
n=5
l=0 (for s orbital)
m = 0 ( As m= -l to +l)
s =+1/2
s =+1/2
