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Some Basic Concepts Of Chemistry

Question
CBSEENCH11008256
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How many grams of the concentrated nitric solution should be used to prepare 250 mL o 2.0M HNO3 ? The concentrated acid is 70% HNO3.

  • 45.0 g conc. HNO3

  • 90.0 g conc. HNO3

  • 70.0 g conc. HNO3

  • 54.0 g conc. HNO3

Solution

A.

45.0 g conc. HNO3

Given, molarity of solution = 2
Volume of solution = 250 mL = 250/1000 = 1/4 L
Molar mass of 
HNO3 = 1+14+3 x 16 = 63 g mol-1
therefore, Molarity
= fraction numerator weight space of space HNO subscript 3 over denominator mass space of space HNO subscript 3 space straight x space volume space of space solution space left parenthesis straight L right parenthesis end fraction therefore comma Weight space of space HNO subscript 3 space equals space molarity space straight x space space mol. mass space straight x space volume space left parenthesis straight l right parenthesis equals 2 space straight x space 63 space straight x space 1 fourth straight g space equals space 31.5 space straight g It space is space the space weight space of space 100 percent sign space HNO subscript 3 But space the space given space acid space is space 70 percent sign space HNO subscript 3 therefore comma its space weight space equals space 31.5 space straight x space 100 over 70 space straight g space equals space 45 space straight g

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