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Thermodynamics

Question
CBSEENCH11008131
Wired Faculty App

Standard entropy of X2, Y2 and XY3 are 60, 40 and 50 JK−1
mol −1, respectively. For the reaction,1/2X2 + 3/2Y2, ΔH = -30 kJ,to be at equilibrium, the temperature will be

  • 1250 K

  • 500 K 

  • 750 K

  • 1000 K

Solution

C.

750 K

1 half space straight X subscript 2 space plus space 3 over 2 straight Y subscript 2 space rightwards arrow space XY subscript 3 space increment straight S subscript reaction space equals space minus space 50 minus open parentheses 3 over 2 space straight x space 40 space plus space 1 half space straight x space 60 close parentheses space equals space minus space 40 space straight J space mol to the power of negative 1 end exponent increment straight G space space equals space increment straight H space minus space straight T increment straight S at space equilibrium space increment straight G space equals space 0 increment straight H space equals space straight T increment straight S 30 space straight x space 10 cubed space equals space straight T space straight x space 40 rightwards double arrow space straight T space equals space 750 space straight K

Some More Questions From Thermodynamics Chapter

What do you understand by the terms: the system and surroundings?

Classify the following into different types of systems:
(i) Tea placed in a cup
(ii) Tea placed in a tea-pot
(iii) Tea placed in a thermosflask. 

Define a closed system.

Define an isolated system.

Define intensive properties.

Define extensive properties.

Why all living systems need to be 'open systems'?

Define state variables of a system.

From thermodynamic point of view, to which system the animals and plants belong?

What is a state function?

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