+91-8076753736[email protected]
logo
logo
-->

Thermodynamics

Question
CBSEENCH11008105
Wired Faculty App

The solubility product of silver bromide is 5.0 x 10-13. The quantity of potassium bromide (molar mass taken as 120 g mol–1)to be added to 1 litre of 0.05 M solution of silver nitrate to start the precipitation of AgBr is

  • 1.2 x 10-10 g 

  • 1.2 x 10-9 g

  • 6.2 x 10-5 g 

  • 5.0 x 10-8 g

Solution

A.

1.2 x 10-10 g 

Ksp of AgBr = [Ag+][Br-] = 5.0 x 10-13
[Ag+] = 0.05 M
left square bracket Br to the power of minus right square bracket space equals space fraction numerator 5.0 space straight x space 10 to the power of negative 13 end exponent over denominator 0.05 end fraction space equals space 1 space straight x space 10 to the power of negative 11 end exponent space straight M
Moles of KBr = 1 x 10-11 x 1 = 1 x 10-11
weight of KBr  1 x 10-11 x 120 = 1.2 x 10-19 g

Some More Questions From Thermodynamics Chapter

Define intensive properties.

Define extensive properties.

Why all living systems need to be 'open systems'?

Define state variables of a system.

From thermodynamic point of view, to which system the animals and plants belong?

What is a state function?

A thermodynamic state function is a quantity

What is reversible process in thermodynamics?

Define irreversible change.

Name the variable that is kept constant in isochoric process and isobaric process.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation