Structure of Atom

Structure of Atom

Question

The ionization energy of He+ is 19.6 x 10–18 J atom–1. The energy of the first stationary state (n = 1) of Li2+ is

  • 4.41 x 10-16 J atom–1

  • -4.41 x 10-17 J atom–1

  • -2.2 x 10-15 J atom–1.

  • 8.82 x 10-17 J atom–1.

Answer

B.

-4.41 x 10-17 J atom–1

Ionisation energy of He+
= 19.6 × 10-18 J
E1 (for H) × Z2= IE
E1 × 4 = – 19.6 × 10-18 J
E1 (for Li2+) = E1 for H × 9
space equals space minus space fraction numerator 19.6 space straight x space 10 to the power of negative 18 end exponent over denominator 4 end fraction space straight x space 9 space space equals space minus 44.1 space straight x space 10 to the power of negative 18 end exponent space straight J
-4.41 x 10-17 J atom–1

More Chapters from Structure of Atom