Question
Consider the reaction: N2 +3H2 → 2NH3 carried out at constant temperature and pressure. If ∆H and ∆U are the enthalpy and internal energy changes for the reaction, which of the following expressions is true?
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∆H = 0
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∆H = ∆U
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∆H < ∆U
-
∆H >∆U
Solution
C.
∆H < ∆U
∆H = ∆U + ∆nRT
∆n = -2
∆H = ∆U - 2RT
∆H < ∆U
