The equilibrium constant for the reaction

$SO subscript 3 space left parenthesis straight g space right parenthesis space rightwards harpoon over leftwards harpoon with space space space space space on top space SO subscript 2 space left parenthesis straight g right parenthesis space plus space 1 half space straight O subscript 2 space left parenthesis straight g right parenthesis$
is K_c = 4.9 × 10^–2. The value of K_c for the reaction'
2SO₂ (g) +O₂(g) ⇌ 2SO₃ (g) will be

416

2.40 × 10^–3

9.8 × 10^–2

4.9 × 10^–2

Solution

416

straight K apostrophe subscript straight c space equals space open parentheses fraction numerator 1 over denominator 4.9 space straight x space 10 to the power of negative 2 end exponent end fraction close parentheses squared space equals space fraction numerator 10 to the power of 4 over denominator 4.9 space straight x space 4.9 end fraction space equals space fraction numerator 100 space straight x 100 over denominator 24.01 end fraction space equals space 4.1649 space space straight x space 100 space equals space 416.49

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