Which one of the following will have largest number of atoms?

1g Au (s)
1g Na (s)
1g Li (s)
1 g of Cl₂(g)

Solution

1g Li (s)

left parenthesis straight i right parenthesis space 1 space straight g space Au left parenthesis straight s right parenthesis space equals space 1 over 197 mol space space space space space space space space space space space space space space space space space space space equals 1 over 197 cross times 6.022 space cross times space 10 to the power of 23 space atoms left parenthesis ii right parenthesis space 1 gNa left parenthesis straight s right parenthesis space equals space 1 over 23 mol space equals space 1 over 23 cross times 6.022 space cross times space 10 to the power of 23 space atom

left parenthesis iii right parenthesis space 1 straight g space Li left parenthesis straight s right parenthesis space equals space 1 over 7 mol space space space space space space space space space space space space space space space space space space equals 1 over 7 cross times 6.022 cross times 10 to the power of 23 space atoms left parenthesis iv right parenthesis space 1 space straight g space of space Cl subscript 2 left parenthesis straight g right parenthesis space equals space 1 over 71 mol space space space space space space space space space space space space space space space space space space space space equals space 1 over 71 cross times 6.022 cross times 10 to the power of 23 space molecules space space space space space space space space space space space space space space space space space space space space equals space 2 over 71 cross times 6.022 space cross times 10 to the power of 23 space atoms

Hence 1 g Li(s) has the largest number of atoms

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