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Some Basic Concepts Of Chemistry

Question
CBSEENCH11008031
Wired Faculty App

What weight of Ca will contain the same number of atoms as are present in 3.2g of sulphur?

Solution

Atomic mass of sulphur = 32 amu
Gram atomic mass of sulphur = 32 g
1 mole of sulphur contains  = 6.023 x 1023 atoms
Now 32 g of sulphur contains
                            = 6.023 x 1023 atoms
3.2 g of sulphur would contain
      equals space fraction numerator 6.023 space cross times space 10 to the power of 23 over denominator 32 end fraction cross times space 3.2 space equals space 6.023 space cross times space 10 to the power of 22 space atoms
   
Gram atomic mass of calcium  = 40 g
    1 mole of calcium  = 40 g
                               = 6.023 x 1023 atoms
Now 6.023 x 1023 atoms of calcium have mass  = 40 g
therefore space space space 6.023 space cross times space 10 to the power of 22 space atoms space of space calcium space will space have space mass space space space space space space space space space space space space space equals space fraction numerator 40 over denominator 6.023 space cross times space 10 to the power of 23 end fraction cross times 6.023 space cross times space 10 to the power of 22 space equals space 4 space straight g

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