Calculate the number of molecules present:
(i) in one drop of water having mass of 0.05 g
(ii) in 34.20 gram of cane sugar (C12H22O11).
(i) 1 mole of H2O = 18 g
= 6.023 x 1023 molecules
Mass of 1 drop of water = 0.05 g
Now 18 g of H2O contains 6.023 x 1023 molecules
0.05 g of
would contain
(ii) Molecular mass of