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Some Basic Concepts Of Chemistry

Question
CBSEENCH11008027

How many atoms and molecules of phosphorus are present in 62 g of phosphorus (P4)?

Solution

Molecular formula of phosphorus = P4
Gram molecular mass of phosphorus (P4)
                                                       
= 4 x 31 = 124 g
124 g of phosphorus contains 6.023 x 1023 molecules of phosphorus
                        therefore 62 g of phosphorus would contain
             
equals space fraction numerator 6.023 space cross times space 10 to the power of 23 over denominator 124 end fraction cross times 62 space molecules space of space phosphorus
equals space 3.011 space straight x space 10 to the power of 23 space molecules space of space straight P subscript 4
space space Now space 1 space mole space of space straight P subscript 4 space equals space 6.023 space cross times space 10 to the power of 23 space molecules
of space straight P subscript 4 space equals space 4 space cross times 6.023 space cross times space 10 to the power of 23 space atoms space of space phosphorus
space straight i. straight e. space 124 space straight g space of space phosphorus space contain
space 4 space cross times space 6.023 space cross times space 10 to the power of 23 space atoms space of space phosphorus

therefore space 62 space straight g space of space phosporus space contain
equals space fraction numerator 4 cross times 6.023 cross times 10 to the power of 23 over denominator 124 end fraction cross times space 62 space atoms space of space phosphorus
equals space 1.2046 space cross times space 10 to the power of 24 space atoms space of space phosphorus.