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Some Basic Concepts Of Chemistry

Question
CBSEENCH11008020

What is the utility of mole concept?

Solution
1. To calculate the mass of one atom of the element.
Mass space of space one space atom space of space element space equals space fraction numerator Gram space atomic space mass over denominator Avogadro apostrophe straight s space number end fraction
2. To calculate the mass of one molecule of the substance.
Mass space of space one space molecule space of space substance equals fraction numerator Gram space molecular space mass over denominator Avogadro apostrophe straight s space number end fraction
3. To calculate the number of atoms and  the number of molecules in a given mass of the element.
The Number of atoms in a given mass of the element. 
                  equals space fraction numerator 6.023 space straight x space 10 to the power of 23 over denominator Gram space atomic space mass end fraction cross times Mass space of space element space in space grams.
space space No. space of space molecules space in space given space mass space of space the space element.
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator Mass space of space element space in space grams over denominator Gram space atomic space mass end fraction

4. To calculate the number of molecules and the number of moles in a given mass of the substance.
No. of molecules in a given mass of a substance
                       equals space fraction numerator 6.023 space cross times space 10 to the power of 23 over denominator Gram space molecular space mass end fraction cross times Mass space of space substance space in space grams
space space space space No. space of space moles space in space straight a space given space mass space of space substance
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator Mass space of space substance space in space grams over denominator Gram space molecular space mass end fraction
5. To calculate the volume occupied at S.T.P. by a given mass of a gas.
Volume occupied at S.T.P. by given mass of a gas
               equals space fraction numerator 22.4 space litres over denominator Gram space moleuclar space mass space of space straight a space gas end fraction cross times space mass space of space gas space in space grams
6. To calculate the number of molecules present in a given volume of a gas at S.T.P.
No. of molecules contained in given volume of gas at S.T.P.
           equals space fraction numerator 6.023 space cross times space 10 to the power of 23 over denominator 22.4 space litres end fraction cross times space volume space of space gas space in space litres space at space straight S. straight T. straight P.
7. To calculate the number of atoms and molecules in the given number of moles of a substance.
No. of atoms in a given number of moles of element
= 6 · 023 × 1023 × No. of moles of element No. of molecules in a given number of moles of substance
= 6·023 × 1023 × No. of moles of substance