Question
The hybridization of orbitals of N atom in NO3-, NO2+ and NH4+ are respectively
-
sp, sp2,sp3
-
sp2 , sp, sp
-
sp, sp3 , sp2
-
Sp2, sp3, sp
Solution
B.
sp2 , sp, sp
NO2+
Number of electron pairs = 2
Number of bond pairs = 2
Number of lone pair = 0
So, the species is linear with sp hybridisation.
NO3-
Number of electron pairs = 3
Number of bond pairs = 3
Number of lone pair = 0
So, the species is trigonal planar with sp2 hybridisation
NH4+
Number of electron pairs = 4
Number of bond pairs = 4
Number of lone pair = 0
So, the species is tetrahedral with sp3 hybridisation.
