Chemical Bonding And Molecular Structure

Question
CBSEENCH11008091

The hybridization of orbitals of N atom in NO3-, NO2+ and NH4+ are respectively

  • sp, sp2,sp3

  • sp2 , sp, sp

  • sp, sp3 , sp2

  • Sp2, sp3, sp

Solution

B.

sp2 , sp, sp

NO2+
Number of electron pairs = 2
Number of bond pairs = 2
Number of lone pair = 0
So, the species is linear with sp hybridisation.
NO3-
Number of electron pairs = 3
Number of bond pairs = 3
Number of lone pair = 0
So, the species is trigonal planar with sp2 hybridisation

NH4+
Number of electron pairs = 4
Number of bond pairs = 4
Number of lone pair = 0
So, the species is tetrahedral with sp3 hybridisation.

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