States of Matter

States of Matter

Question

The compressibility factor for a real gas at high pressure is

  • 1 plus RT over pb
  • 1
  • 1 plus pb over RT
  • 1 minus pb over RT

Answer

C.

1 plus pb over RT

Vander Waal's equation for one mole of real gas is
open parentheses straight p plus straight a over straight V squared close parentheses space left parenthesis straight v minus straight b right parenthesis space equals space RT
When space pressure space is space high space straight p space greater than greater than straight a over straight V squared
such space that space open parentheses straight p space plus straight a over straight V squared close parentheses space equals space straight p
thus comma space straight p left parenthesis straight v minus straight b right parenthesis space equals space RT
pV minus pb space equals space RT
pv space equals space RT space plus pb
therefore space COmpressibillity space factor comma
straight z space equals space pV over RT space equals space open parentheses 1 plus pb over RT close parentheses

More Chapters from States of Matter