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Chemical Bonding And Molecular Structure

Question
CBSEENCH11008075

Stability of the species Li2, Li2 and Li2+ increases in the order of:

  • Li2 < Li2+ < Li2-

  • Li2 < Li2+ < Li2 

  • Li2< Li2 < Li2+

  •  Li2 <Li2< Li2+

Solution

B.

Li2 < Li2+ < Li2 

Li subscript 2 left parenthesis 6 right parenthesis space equals space straight sigma 1 straight s squared space straight sigma asterisk times 1 straight s squared straight sigma 2 straight s squared
straight B. straight O space equals space fraction numerator 4 minus 2 over denominator 2 end fraction space equals space 1
Li subscript 2 superscript plus space left parenthesis 5 right parenthesis space equals space straight sigma 1 straight s squared space straight sigma asterisk times 1 straight s squared straight sigma 2 straight s to the power of 1
straight B. straight O space equals space fraction numerator 3 minus 2 over denominator 2 end fraction space equals 0.5
Li subscript 2 superscript minus space left parenthesis 7 right parenthesis space space equals space space straight sigma 1 straight s squared space straight sigma asterisk times 1 straight s squared straight sigma 2 straight s squared straight sigma asterisk times 2 straight s to the power of 1
straight B. straight O space equals space fraction numerator 4 minus 3 over denominator 2 end fraction space equals space 0.5
Li2+ is more stable than Li2 because Li2 has more numbers of antibonding electrons.