Question
A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.00C. As it does so, it absorbs 208J of heat. The values of q and w for the process will be:(R = 8.314 J/mol K) ( ln 7.5 = 2.01)
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q =+208J, W = - 208 J
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q =-208 J, W =-208 J
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q=-208J, W = +208 J
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q =+208 J, W = +208 J
Solution
A.
q =+208J, W = - 208 J
From first law of thermodynamics, ΔE = q+W for an isothermal expansion.
Hence, q =-W
q= +208 J
W =-208 J [expansion work]
